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4k^2+30k-16=0
a = 4; b = 30; c = -16;
Δ = b2-4ac
Δ = 302-4·4·(-16)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-34}{2*4}=\frac{-64}{8} =-8 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+34}{2*4}=\frac{4}{8} =1/2 $
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